35/(1+3e^-0,2x)=5

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Solution for 35/(1+3e^-0,2x)=5 equation: 


D( x )

3*e^-0.2*x+1 = 0

3*e^-0.2*x+1 = 0

3*e^-0.2*x+1 = 0

3*e^-0.2*x+1 = 0 // - 1

3*e^-0.2*x = -1 // : 3*e^-0.2

x = -1/(3*e^-0.2)

x in (-oo:-1/(3*e^-0.2)) U (-1/(3*e^-0.2):+oo)

35/(3*e^-0.2*x+1) = 5 // - 5

35/(3*e^-0.2*x+1)-5 = 0

35/(3*e^-0.2*x+1)+(-5*(3*e^-0.2*x+1))/(3*e^-0.2*x+1) = 0

35-5*(3*e^-0.2*x+1) = 0

30-15*e^-0.2*x = 0

(30-15*e^-0.2*x)/(3*e^-0.2*x+1) = 0

(30-15*e^-0.2*x)/(3*e^-0.2*x+1) = 0 // * 3*e^-0.2*x+1

30-15*e^-0.2*x = 0

30-15*e^-0.2*x = 0 // - 30

-15*e^-0.2*x = -30 // : -15*e^-0.2

x = -30/(-15*e^-0.2)

x = 2*e^0.2

x = 2*e^0.2

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